Please solve q 180?

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Please solve q 180?

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Answer 1 · 2018-04-07T16:10:02

answer is (3)
i.e. 650 gm

Explanation:

Upthrust on ball = weight of displaced water
= $V σ g = (\frac{m}{ρ}) σ g$ $V sigmag=(m/rho)sigma g$
= $\frac{40}{0.8} \cdot 1 \cdot g$ $40/0.8*1*g$
= $50 g$ $50g$ dyne or, $50 g m$ $50gm$
As the ball is sunk into the water with a pin by applying downward force equal to upthrust on it.
So reading of weighing pan = weight of water + downward force against upthrust
= 600 + 50 = 650 gm

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Please solve q 180?

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