Evaluate: integration[sin(x^0)dx]?

1 Answer
Apr 7, 2018

(sin1)*x+C

or

-pi/180cos(180/pix)+C

Explanation:

First Answer
if You mean x to the power of zero:
First, sinx^0=sin1
so it's integration will be easy with the power rule:
intsin1dx=(sin1)*x+C
.

Second Answer
If you mean x degree then this will be the answer:
x_(degree)=180/pix_(radian)

and by substituting you get
intsin(x^0)*dx=intsin(180/pix)*dx

=-cos(180/pix)/(180/pi)+C

=-pi/180cos(180/pix)+C