How do you simplify $3 (4 + 5 s) - 12 + (- 3 s)$ $3 (4 + 5s ) - 12 + ( - 3s )$ ?

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How do you simplify $3 (4 + 5 s) - 12 + (- 3 s)$ $3 (4 + 5s ) - 12 + ( - 3s )$ ?

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Answer 1 · 2018-04-07T13:07:29

$12 s$ $12s$

Explanation:

$3 (4 + 5 s) - 12 + (- 3 s)$ $3(4+5s)-12+(-3s)$

$= 12 + 15 s - 12 - 3 s$ $=12+15s-12-3s$

$= (12 - 12) + (15 s - 3 s)$ $=(12-12)+(15s-3s)$

$= 0 + 12 s$ $=0+12s$

$= 12 s$ $=12s$

Answer 2 · 2018-04-07T13:21:25

The answer is $12 s$ $12s$ .

Explanation:

Firstly you have to open the bracket $3 (4 + 5 s)$ $3(4+5s)$ it will be $12 + 15 s$ $12 +15s$ and the second bracket $+ (- 3 s)$ $+ (-3s)$ will be $- 3 s$ $-3s$ . So your equation will be $12 + 15 s - 12 - 3 s$ $12 +15s -12 - 3s$ then collect like terms, it will be $12 - 12 + 15 s - 3 s$ $12 -12 +15s -3s$ , then it will be $12 s$ $12s$ .

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How do you simplify $3 (4 + 5 s) - 12 + (- 3 s)$ $3 (4 + 5s ) - 12 + ( - 3s )$ ?

2 Answers

Explanation:

Explanation:

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How do you simplify 3(4+5s)−12+(−3s)3 (4 + 5s ) - 12 + ( - 3s )?

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How do you simplify $3 (4 + 5 s) - 12 + (- 3 s)$ $3 (4 + 5s ) - 12 + ( - 3s )$ ?