How do you factor the trinomial #x^2+8x+12#?

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Answer 1 · 2018-04-06T19:51:17

#(x+2)(x+6)#

#2+6=8#

#2*6=12#

#(x+2)(x+6)#

Check:
#= x^2 + 6x + 2x +12#
#= x^2 + 8x + 12#

Answer 2 · 2018-04-06T19:57:58

#(x+6)(x+2)#

#12=6*2#; where #6+2=8#

#12=3*4#; where #3+4=7#

#12=12*1#, where #12+1=13#

So we will take #6# and #2#.

Now;

#x^2+8x+12#

#x^2+6x+2x+12#

#x(x+6)+2(x+6)#

#(x+6)(x+2)#