What is the chemical formula for the following ionic compounds: Barium Sulfate, Manganese(II) Fluoride?

1 Answer
zhirou
Apr 6, 2018

Barium sulfate is #BaSO_4#, and manganese(II) fluoride is #MnF_2#.

Explanation:

To answer these questions, we have to keep in mind that, in compounds, the overall charge needs to add up to #0#.

  • Barium sulfate is made up #Ba^(2+)# and #SO_4^(2-)#, so, to get the overall charge to equal #0#, the chemical formula would be #BaSO_4#.
  • Manganese(II) fluoride is #Mn^(2+)# and #F^-#. To get the overall charge to equal #0#, the formula would be #MnF_2#.
Related questions
Impact of this question
3452 views around the world
You can reuse this answer
Creative Commons License