How do you factor completely #w^2 - w^2 y^4#?

Question

How do you factor completely #w^2 - w^2 y^4#?

1 Answer

Impact of this question

1401 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-04T19:22:51

#w^2(1+y)(1-y)(1+y^2)#

Explanation:

This is just a difference of squares. When you have #a^2 - b^2#, it's is equal to #(a+b)(a-b)#. Just simply expand it to see why. In this case, it would be

#(w)^2 - (w*y^2)^2#

#(w- wy^2)(w + wy^2)#

#w^2(1-y^2)(1+y^2)#

#w^2(1+y)(1-y)(1+y^2)#

Science

Math

Humanities

... and beyond

How do you factor completely #w^2 - w^2 y^4#?

1 Answer

Explanation:

Related questions

Impact of this question