How do you solve the system of equations #2x - 5y = - 1# and #4x - 5y = 13#?

1 Answer
jk.13
Apr 4, 2018

#(x,y)=(7,3)#

Explanation:

#2x=5y-1#
#x=5/2y-1/2# solve for #x# in terms of #y# in the first equation
#4(5/2y-1/2)-5y=13# plug into other equation
#10y-2-5y=13# distribute
#5y-2=13# combine like terms
#5y=15#
#y=3#
Now, going back to the other equation
#2x-5(3)=-1# plug in value of y
#2x-15=-1#
#2x=14#
#x=7#

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