How do you write #x^2+ 4x+3# in factored form?

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Answer 1 · 2018-04-03T12:51:48

#(x+3)(x+1)#

#x^2+4x+3# is in the general form #x^2+bx+c#

which can also be written as
#x^2+("sum of roots")x+("product of roots")#

which basically means that you need to find TWO roots that when added together equal to 4 and when multiplied together equal to 3.

So the numbers that make the above statement true are
#x=1 and x=3#

Answer 2 · 2018-04-03T12:52:04

#x²+4x+3=(x+1)(x+3)#

#x²+4x+3=x²+3x+x+3#
#=x(x+3)+x+3#
#=(x+1)(x+3)#
\0/ here's our answer !