How do you evaluate $- y^{2} + 3 (4 y^{2} - 7 y + 5) - (- 3 y^{2} + y - 6)$ $-y^{2}+3(4y^{2}-7y+5)-(-3y^{2}+y-6)$ ?

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Answer 1 · 2018-04-02T10:27:06

$- y^{2} + 3 (4 y^{2} - 7 y + 5) - (- 3 y^{2} + y -) = 14 y^{2} - 22 y + 21$ $-y^2+3(4y^2-7y+5)-(-3y^2+y-) = 14y^2-22y+21$

1) We expand the brackets.
2) We collect like terms (y's with the same power).
3) We write the Solution achieved.

How do you evaluate −y2+3(4y2−7y+5)−(−3y2+y−6)-y^{2}+3(4y^{2}-7y+5)-(-3y^{2}+y-6)?