How do you rationalize the denominator and simplify 6/(sqrt(2x))6√2x?

2 Answers
Shubh
Apr 1, 2018

[3sqrt(2x)]/x3√2xx

Explanation:

6/(sqrt(2x))6√2x
6/(sqrt(2x))*[(cancel-sqrt(2x))/(cancel(-)sqrt(2x))]
which will give,
(cancel(6)sqrt(2x))/(cancel(2)x)=[3sqrt(2x)]/x

Jim G.
Apr 1, 2018

(3sqrt(2x))/x

Explanation:

"note that "sqrtaxxsqrta=a

"to rationalise the denominator, that is eliminate the"
"radical from the denominator then"

"multiply numerator/denominator by "sqrt(2x)

rArr6/(sqrt(2x))xxsqrt(2x)/sqrt(2x)

=(6sqrt(2x))/(2x)=(3sqrt(2x))/x

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