How to solve this vector unit normal from Vector Calculus?:

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How to solve this vector unit normal from Vector Calculus?:

$r (t) = \sqrt{2} t i + e^{t} j - e^{- t} k$ $r(t)=sqrt(2)ti+e^tj-e^-tk$
$t = 0$ $t=0$

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Answer 1 · 2018-03-31T06:02:17

answer= $\sqrt{2}$ $sqrt2$

Explanation:

firstly, differentiate the quantity,
= $\sqrt{2}$ $sqrt2$ + te $j$ $j$ + te $k$ $k$
now, put the value of $t$ $t$ i.e. 0
$\sqrt{2}$ $sqrt2$ + (0)e $j$ $j$ + (0)e $k$ $k$
on solving further,
=) $\sqrt{2}$ $sqrt2$ is the required answer.

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How to solve this vector unit normal from Vector Calculus?:

$r (t) = \sqrt{2} t i + e^{t} j - e^{- t} k$ $r(t)=sqrt(2)ti+e^tj-e^-tk$
$t = 0$ $t=0$

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

How to solve this vector unit normal from Vector Calculus?:

r(t)=√2ti+etj−e−tkr(t)=sqrt(2)ti+e^tj-e^-tk t=0t=0

1 Answer

Explanation:

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Impact of this question

$r (t) = \sqrt{2} t i + e^{t} j - e^{- t} k$ $r(t)=sqrt(2)ti+e^tj-e^-tk$
$t = 0$ $t=0$