Let f(x) = x2 − 4 and g(x) = 4x − 3, how do you find (f − g)(−6)?

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Let f(x) = x2 − 4 and g(x) = 4x − 3, how do you find (f − g)(−6)?

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Answer 1 · 2018-03-31T01:52:41

$59$ $59$

Explanation:

$(f - g) (x) = f (x) - g (x)$ $(f-g)(x)=f(x)-g(x)$ . so $(f - g) (x) = x^{2} - 4 x - 1$ $(f-g)(x)=x^2-4x-1$ . Plugging in -6, you get that the answer is $59$ $59$

Answer 2 · 2018-03-31T01:53:17

$(f - g) (- 6) = 59$ $(f-g)(-6)=59$

Explanation:

$(f - g) (- 6)$ $(f-g)(-6)$ = $f (- 6) - g (- 6)$ $f(-6)-g(-6)$

$f (- 6) = {(- 6)}^{2} - 4$ $f(-6)=(-6)^2-4$
$f (- 6) = 36 - 4$ $f(-6)=36-4$
$f (- 6) = 32$ $f(-6)=32$

$g (- 6) = 4 (- 6) - 3$ $g(-6)=4(-6)-3$
$g (- 6) = - 24 - 3$ $g(-6)=-24-3$
$g (- 6) = - 27$ $g(-6)=-27$

$f (- 6) - g (- 6)$ $f(-6)-g(-6)$
$32 - (- 27)$ $32-(-27)$
$32 + 27$ $32+27$
$59$ $59$

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Let f(x) = x2 − 4 and g(x) = 4x − 3, how do you find (f − g)(−6)?

2 Answers

Explanation:

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