If sinx=55/65 then sinx +cosx = ?

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Answer 1 · 2018-03-29T11:04:28

$89.6/65$

Sine is the $o/h$ so we know the opposite is 55 and the hypotenuse is 65

So from this we can figure out the adjacent using Pythagoras

$c^2=a^2+b^2$

$(65)^2=(55)^2+b^2$

$4225=3025+b^2$

$1200=b^2$

$b=34.6$ (3sf)

$Cos(x)=a/h=34.6/65$

So $sin(x)+cos(x)=(55+34.6)/65=89.6/65$