Derivative of f(x)=e^x^2?

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Answer 1 · 2018-03-29T04:52:36

$f'(x)=2xe^(x^2)$

We have a chain rule we have the outside function $f(u)=e^u$

and the inside function $u=x^2$

Chain rule is derive both functions and then multiply the derivatives

so $f'(u)*u'$

$f'(u)=e^u$
$u'=2x$

Mutply derivatives

$2xe^u=2xe^(x^2)=f'(x)$