How do you multiply # sqrt 2 / sqrt 10#?

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Answer 1 · 2018-03-29T04:41:40

#1/sqrt5#

Rule is #sqrta/sqrtb=sqrt(a/b)#

#sqrt(2/10)#

#sqrt(1/5)# as #sqrt1=1# answer #1/sqrt5#

Answer 2 · 2018-03-29T04:43:17

#1/sqrt5# or #sqrt5/5#

#sqrt10 = sqrt{2*5} = sqrt2sqrt5#

So #sqrt2/sqrt10 = sqrt2/{sqrt2sqrt5} = 1/sqrt5 = 1/sqrt5*sqrt5/sqrt5 = sqrt5/5#