How do you find the domain and range for $y = - sin 0.25 x$ $y = -sin 0.25x$ ?

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How do you find the domain and range for $y = - sin 0.25 x$ $y = -sin 0.25x$ ?

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Answer 1 · 2018-03-29T04:13:02

Range $[- 1.1]$ $[-1.1]$
Domain $(- \infty, \infty)$ $(-oo,oo)$

Explanation:

range doesn't change as in the equation $A sin (B (x - C) + D$ $Asin(B(x-C)+D$

Only A and D change the range and so the range isn't changed as there is no vertical translation or stretch. So it retains the normal range of between 1 and -1. The minus at the beginning merely inverts it along the x axis

For the domain only the parts B and C can effect it we can see that the B is 0.25 so this is quadrupling the period but as the domain was $(- \infty, \infty)$ $(-oo, oo)$ From negative infinity to postive there is no change in the domain.

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How do you find the domain and range for $y = - sin 0.25 x$ $y = -sin 0.25x$ ?

1 Answer

Explanation:

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How do you find the domain and range for $y = - sin 0.25 x$ $y = -sin 0.25x$ ?