How do you solve #-7m+9=29-2m#?

3 Answers
Jacobi J.
Mar 28, 2018

#m=-4#

Explanation:

We can add #2m# to both sides to get

#-5m+9=29#

Next, we can subtract #9# from both sides to get

#-5m=20#

Lastly, we can divide both sides by #-5# to get

#m=-4#

Hope this helps!

Tal G. · Jacobi J.
Mar 28, 2018

#-7m+2m=29-9#

#-5m=20#

#m=-4#

Explanation:

In order to solve this equation you need to move the letters to the left and the numbers which do not have any letters to the right.
also, when moving #-2m# to the other side it becomes #+2m#.

Ben
Mar 28, 2018

Move all constants to one side, and all #m#-terms to the other. When you divide the constants by #m#'s coefficient, you will find that #m=-4#

Explanation:

First step is to move all constants to one side. Let's move them to the Right Hand Side (RHS). We will do this by subtracting both sides by constants on the Left Hand Side (LHS):

#-7m cancel(+9color(red)(-9))=29-2mcolor(red)(-9)#

#rArr -7m=20-2m#

Next, we'll move the #m#-terms to the LHS. We'll do this by subtracting both sides by the whole value:

#-7mcolor(red)(-(-2m))=20-2mcolor(red)(-(-2m))#

#rArr-7mcolor(red)(+2m)=20cancel(-2mcolor(red)(+2m))#

#rArr-7mcolor(red)(+2m)=20#

#rArr(-7+2)m=20#

#rArr-5m=20#

Finally, we'll divide both sides by #m#'s coefficient:

#(cancel(-5)m)/cancel(color(red)(-5))=20/(color(red)(-5))#

#color(green)(rArr m=-4)#

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