How do you solve #-3- 6x = 9#?

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Answer 1 · 2018-03-28T17:59:28

#-3-6x=9# (add 3 to both sides)

#-6x = 12# (divide by -6 on both sides to isolate the variable)

#(-6x)/-6 = (12)/-6#

#x=-2#

Plug the answer back into the equation to check the answer:

#-3-6(-2)=9#

#-3-(-12)=9#

#-3+12=9#

#9=9#