How do you solve #Log(x)-2=log(x-4)#?

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Answer 1 · 2018-03-28T16:44:31

x=4/99

#log(x)-2=log(x-4)#

#x/10^2=x-4,iff x>0 and x>4#

#x/10^2-x=-4#

#x-100x=-400#

#-99x=-400#

#x=400/99#

x>4 so the solution is correct.