How do you use the laws of exponents to simplify the expression $((3^2)/(3^-3))^(3/5)$ ?

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Answer 1 · 2018-03-28T15:45:28

It simplifies to $27$ .

$(\frac{3^2}{3^{-3}})^{\frac{3}{5}}=(3^{(2+3)})^{\frac{3}{5}}=(3^5)^{\frac{3}{5}}=3^{5\cdot \frac{3}{5}}=3^3=27$

Answer 2 · 2018-03-28T15:46:41

$3^3$ . See below

You have several ways to resolve. This could be the simpliest...

First operate whithin the braquets using laws of exponents

$3^2/3^(-3)=3^(2-(-3))=3^5$

Now, apply exponent $3/5$ to this result

$(3^5)^(3/5)=3^(5·3/5)=3^3$

How do you use the laws of exponents to simplify the expression ((3^2)/(3^-3))^(3/5) ((3^2)/(3^-3))^(3/5)?