How do you evaluate 7d – 5c if d = 7 and c = 3?

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Answer 1 · 2018-03-27T13:00:42

$34$ $34$

Given: $7 d - 5 c$ $7d-5c$

Plug in $d = 7, c = 3$ $d=7,c=3$ , we get,

$7 \cdot 7 - 5 \cdot 3$ $7*7-5*3$

$= 49 - 15$ $=49-15$

$= 34$ $=34$

Answer 2 · 2018-03-27T13:04:16

49-15=34

First begin by substituting each variable for the number amount that is given (7 in for d and 3 for c). It will end up looking something like this:

$7 (7) - 5 (3) or (7 \cdot 7) - (5 \cdot 3)$ $7(7)-5(3) or (7*7)-(5*3)$

It's just simple multiplication and subtraction from here on out:

$7 \cdot 7 = 49 and - 5 \cdot 3 = 15$ $7*7=49 and -5*3=15$

So all simplified we get:

$49 - 15 = 34$ $49-15=34$