How do you solve for $B$ $B$ in $A = 3 (B + C)$ $A=3(B+C)$ ?

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How do you solve for $B$ $B$ in $A = 3 (B + C)$ $A=3(B+C)$ ?

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Answer 1 · 2018-03-25T22:17:10

B= $\frac{A}{3} - C = B$ $A/3-C=B$

Explanation:

$\frac{A}{3} = B + C$ $A/3=B+C$ then $\frac{A}{3} - C = B$ $A/3 -C=B$
In the first step you have to divide both sides by 3 so that removes it on the RHS.
In step two minus the c by both sides and this removes it from the RHS leaving you with the answer.

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How do you solve for $B$ $B$ in $A = 3 (B + C)$ $A=3(B+C)$ ?

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Science

Math

Humanities

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How do you solve for BB in A=3(B+C)A=3(B+C)?

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Explanation:

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Impact of this question

How do you solve for $B$ $B$ in $A = 3 (B + C)$ $A=3(B+C)$ ?