What's the answer??

Question

#sec^2#(-x) - #tan^2#(-x) = ?

900 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-24T17:05:24

1

#sec(-x)=sec(x)#
#sec^2(-x)=sec^2(x)#

#tan(-x)=-tan(x)# but since its squared it becomes
#tan^2(-x)=tan^2(x)#

So,
#sec^2(-x)-tan^2(-x)=sec^2(x)-tan^2(x)#

And #sec^2(x)-tan^2(x)=1#