How do you graph #y=-x +4# by plotting points?

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Answer 1 · 2018-03-24T00:37:59

Answer below.

The y-intercept is 4 so you graph the point (0,4).

When #x=0#,

#y=-(0)+4#

#y=4#

Next, you know the slope is #-x#, which is also #(-1)/1x#, so you

would go down 1 unit and right 1 unit on the graph. This method is

using #(rise)/(run)#. Then plot the points using the slope.

#color(blue)(Or)# you can find the points algebraically,

When #x=1#,

#y=-(1)+4#

#y=3#

When #x=2#,

#y=-(2)+4#

#y=2#

#"and so on."#

graph{-x+4 [-10, 10, -5, 5]}