How do you translate "the product of 3 and x divided by the sum of x and y" into an algebraic expression?

The product of 3 and x divided by the sum of x and y is

#(Product of 3 and x)/(Sum of x and y)#.

Okay break it into smaller parts. The product of #3 and x# is #3*x# um of #x and y# is #x+y#

Now, we get

#(3*x)/(x+y)#

and that's it

#color(blue)("Before we start have a think about this")#

Although not normally done you can write whole number in fraction format.

Example:
Consider the numbers #color(white)("ddd...")1,color(white)(".")2,color(white)("d")3,color(white)("d")4,color(white)("d")5" and so on"#

You may if you chose write #color(white)(.) 1/1,2/1,3/1,4/1,5/1" and so on."#

I will be using this.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Answering the question")#
The product of 3 and x: #color(white)("d")............color(white)("d") 3xx x ->color(white)("d")3x#
divided by: #color(white)("d")........................................->color(white)("d")3x-:?#
The sum : #color(white)("d").........................................->color(white)("d")3x-:(?+?)#
of #x and y: color(white)("d")......................................->color(white)("d")3x-:(x+y)#

This is the same as #color(white)("d")3x -:(x+y)/1#

Turn the #(x+y)/1# upside down and change the sign from divide to multiply.

#3x xx1/(x+y ) -> (3x)/(x+y)#