If $f (x) = x^{2} - 2$ $f(x)=x^2-2$ and $g (x) = x - 3$ $g(x)=x-3$ , what is $(f \circ g) (x)$ $(f@g)(x)$ ?

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Answer 1 · 2018-03-21T01:28:15

The answer is ${(x - 3)}^{2} - 2$ $(x-3)^2-2$

$(f o g) (x)$ $(fog)(x)$

Substitute g(x)

$= f (x - 3)$ $=f(x-3)$

Plug the value of x into f(x) equation

$= {(x - 3)}^{2} - 2$ $=(x-3)^2-2$

If needed, you can also factor out the ${(x - 3)}^{2}$ $(x-3)^2$ part.

If f(x)=x^2-2f(x)=x2−2f(x)=x^2-2 and g(x)=x-3g(x)=x−3g(x)=x-3, what is (f@g)(x)(f∘g)(x)(f@g)(x)?