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How do you factor # 9y^2 - 1 #?

1 Answer

Mar 19, 2018

#9y^2-1=(3y+1)(3y-1)#

Explanation:

#9y^2-1#
#=(3y)^2-(1)^2#
Using the identity #a^2-b^2=(a+b)(a-b),#
You can further simplify #((3y)^2-(1)^2)# as
#(3y)^2-(1)^2=(3y+1)(3y-1)#

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