What volume of 0.125 M KMnO4 is required to yield 0.180 mol Of potassium permanganate KMnO4?

1 Answer
Kilsi ยท NJ
Mar 18, 2018

1.44 " L"1.44 L

Explanation:

Recall that molarity is a measure of concentration in terms of moles of solute per volume of solution. Assuming that the we are using the standard units for molarity "M"= "moles"/"liters"M=molesliters,

"volume"= (0.180 " mol" " KMnO"_4)/(0.125 " M" " KMnO"_4)volume=0.180 mol KMnO40.125 M KMnO4= color(blue)(1.44 " L")1.44 L

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