How do you solve #-6= - 8- 3n - 4#?

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Answer 1 · 2018-03-17T22:14:16

#n=-2 #

We start with:

#-6 = -8 - 3n - 4#

We need to isolate #n#. Let's start by combining the constant terms on the RHS of the equation. #-8 - 4 = -12#, so:

#-6 = -3n -12#

Now let's add #12# to both sides of the equation:

#-6color(orange)(+12) = -3n - 12 color(orange)(+12)#

#6 = -3n#

Now we simply have to divide by #-3# on both sides:

#6 color(orange)(/-3) = -3n color(orange)(/-3)#

#color(green){-2 = n}#