What is the molarity of 2.4 moles KBr in 4 L solution?

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Answer 1 · 2018-03-16T14:25:34

$0.6 \ "M"$

We got $2.4 \ "mol"$ of potassium bromide dissolved in $4 \ "L"$ of the solution.

Molarity is expressed through the equation:

$"molarity"="moles of solute"/"liters of solution"$

So, plugging in values for the equation, we get:

$"molarity"=(2.4 \ "mol")/(4 \ "L")$

$=0.6 \ "mol/L"$

Another way of writing molarity is in $"M"$ , and $1 \ "M"=1 \ "mol/L"$ .

So, the molarity of this solution is $0.6 \ "M"$ .

Answer 2 · 2018-03-16T14:28:19

The defination of molarity gives us,

$molarity = "number of moles of solute"/"volume of solution in L"$

Put in the values from the question,

$M = (2.4 " moles of KBr") / (4L " of solution"$

$M = 0.6$ mol/L