How do you simplify ${(4 p^{3} q^{4})}^{3}$ $(4p ^ { 3} q ^ { 4} ) ^ { 3}$ ?

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Answer 1 · 2018-03-16T12:33:36

$64 p^{9} q^{12}$ $64p^9q^12$

${(4 p^{3} q^{4})}^{3} = (4^{3}) \cdot {(p^{3})}^{3}$ $(4p^3q^4)^3=(4^3)*(p^3)^3$ ${(q^{4})}^{3}$ $(q^4)^3$
$= 64 p^{9} q^{12}$ $=64p^9q^12$

How do you simplify (4p ^ { 3} q ^ { 4} ) ^ { 3}(4p3q4)3(4p ^ { 3} q ^ { 4} ) ^ { 3}?