Does the point (_2.5, 3.5) lie inside,outside or on the circle x^2+y^2=25 ?

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Does the point (_2.5, 3.5) lie inside,outside or on the circle x^2+y^2=25 ?

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Answer 1 · 2018-03-14T17:05:44

The point is inside the circel

Explanation:

$x^{2} + y^{2} = 25 ∣ ∣ - x^{2} ∣ ∣ \sqrt{}$ $x^2+y^2=25|-x^2|sqrt()$
$y = \sqrt{25 - x^{2}}$ $y=sqrt(25-x^2)$
$y = \sqrt{r^{2} - x^{2}}$ $y=sqrt(r^2-x^2)$
$r^{2} = 25 ∣ \sqrt{}$ $r^2=25|sqrt()$
$r = 5$ $r=5$

$p_{1} = (2.5, 3.5)$ $p_1=(2.5,3.5)$
$\sqrt{{2.5}^{2} + {3.5}^{2}} \approx 4.301 < 5$ $sqrt(2.5^2+3.5^2)~~4.301<5$
The point is inside the circel

graph{(x^2+y^2-25)((y-3.5)^2-0.01+(x-2.5)^2)=0 [-11.1, 11.09, -5.55, 5.55]}

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Does the point (_2.5, 3.5) lie inside,outside or on the circle x^2+y^2=25 ?

1 Answer

Explanation:

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