Does the point (_2.5, 3.5) lie inside,outside or on the circle x^2+y^2=25 ?

1 Answer
Martin C.
Mar 14, 2018

The point is inside the circel

Explanation:

#x^2+y^2=25|-x^2|sqrt()#
#y=sqrt(25-x^2)#
#y=sqrt(r^2-x^2)#
#r^2=25|sqrt()#
#r=5#

#p_1=(2.5,3.5)#
#sqrt(2.5^2+3.5^2)~~4.301<5#
The point is inside the circel

graph{(x^2+y^2-25)((y-3.5)^2-0.01+(x-2.5)^2)=0 [-11.1, 11.09, -5.55, 5.55]}

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