How do you evaluate `2\frac{1}{3]-1\frac{1}{2}`?

Step 1: You have to Multiply the `3` and the `2` together and then add the `1` and that would all be over `3`. Then you get

`2 1/3 = (2 xx 3 + 1)/3 = 7/3`

Step 2: You do the same thing which is `2` times `1` and then add `1` and that would be all over `2`. Then you get

`1 1/2 = (1 xx 2 + 1)/2 = 3/2`

Step 3: Combine together as

`7/3 - 3/2`

Next, you have to have a common denominator of `6`. `7/3` times `2` both top and bottom. Then `3/2` is going to be times `3` both top and bottom.

`7/3 xx 2/2 = (7 xx 2)/(3 xx 2)`

`3/2 xx 3/3 = (3 xx 3)/(2 xx 3)`

Next, multiply top and bottom fractions individually, which gets to be

`14/6 - 9/6 = (14 - 9)/6 = 5/6`

First, change the mixed fractions into improper fractions by multiplying the whole number by the denominator and then adding the numerator.

`2 1/3= (2xx3+1)/3 = 7/3`

`1 1/2= (1xx2+1)/2 = 3/2`

Next, find a common denominator and then multiply the top and the bottom by the same number.

`7/3 xx 2/2 = 14/6`

`3/2 xx 3/3 = 9/6`

Subtract the numerators.

`14-9= 5`

Make sure to keep the denominator.

`5/6`