How do you evaluate $2 (3 x^{2}) (2 x^{2} + 3 x - 5)$ $2( 3x ^ { 2} ) ( 2x ^ { 2} + 3x - 5)$ ?

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Answer 1 · 2018-03-12T12:41:42

$12 x^{4} + 18 x^{3} - 30 x^{2}$ $12x^4 +18x^3-30x^2$

Well, the idea is that you multiply through. The easy bit is to start with $2 (3 x^{2})$ $2(3x^2)$

$2 (3 x^{2}) (2 x^{2} + 3 x - 5)$ $2(3x^2)(2x^2+3x-5)$

$\Rightarrow (6 x^{2}) (2 x^{2} + 3 x - 5)$ $=> (6x^2)(2x^2+3x-5)$

Then you multiply $(6 x^{2})$ $(6x^2)$ by every term in $(2 x^{2} + 3 x - 5)$ $(2x^2+3x-5)$

$\Rightarrow 12 x^{4} + 18 x^{3} - 30 x^{2}$ $=> 12x^4 +18x^3-30x^2$

How do you evaluate 2( 3x ^ { 2} ) ( 2x ^ { 2} + 3x - 5)2(3x2)(2x2+3x−5)2( 3x ^ { 2} ) ( 2x ^ { 2} + 3x - 5)?