If $a = 12, b = 9$ $a=12, b=9$ , and $c = 4$ $c=4$ , what is $\frac{2 c^{3} - a b}{4}$ $(2c^3-ab)/4$ ?

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Answer 1 · 2018-03-11T19:12:59

$5$ $5$

Substitute all the values you have into the given expression

$\frac{2 \cdot 4^{3} - 12 \cdot 9}{4}$ $(2*4^3-12*9)/4$

Simplify

$\frac{20}{4} = 5$ $20/4=5$

Answer 2 · 2018-03-11T19:14:12

5

Plug all inside:
$\frac{2 \cdot 4^{3} - 12 \cdot 9}{4}$ $(2*4^3 - 12*9)/ 4$ = $\frac{128 - 108}{4}$ $(128 - 108)/4$ = $\frac{20}{4} = 5$ $20/4 = 5$

If a=12,b=9a=12, b=9, and c=4c=4, what is 2c3−ab4(2c^3-ab)/4?