If #a=12, b=9#, and #c=4#, what is #(2c^3-ab)/4#?

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Answer 1 · 2018-03-11T19:12:59

#5#

Substitute all the values you have into the given expression

#(2*4^3-12*9)/4#

Simplify

#20/4=5#

Answer 2 · 2018-03-11T19:14:12

5

Plug all inside:
#(2*4^3 - 12*9)/ 4# = #(128 - 108)/4# = #20/4 = 5#