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How do you multiply #(x^ { - 3} y ^ { - 1} ) ^ { - 1} ( x ^ { - 3} y ^ { 0} ) ^ { 2}#?

1 Answer

Mar 11, 2018

The Answer is #x^-3y#.

Explanation:

This can be divided into 2 parts :
1. #(x^-3y^-1)^-1# = #x^3y#
2. #(x^-3y^0)^2# = #x^-6y^0# = #x^-6# because #y^0# = 1.

therefore the answer becomes #(x^3y)(x^-6)# = #x^-3y#

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