What is the standard form of $y= (-4x+4)^3-(5x+12)^2$ ?

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Answer 1 · 2018-03-11T05:30:42

$y=-64x^3+167x^2-312x-80$

The standard form of a cubic function is :

$y=ax^3+bx^2+cx+d$

Therefore after expanding

$(-4x-4)^3$

= $-64x^3+192x^2-192x+64$

and

$(5x+12)^2$

= $25x^2+120x+144$

We can join the 2 expressions

$y=(-64x^3+192x^2-192x+64) - (25x^2+120x+144)$

$y=-64x^3+167x^2-312x-80$

What is the standard form of y= (-4x+4)^3-(5x+12)^2 y= (-4x+4)^3-(5x+12)^2?