How do you divide and simplify $\frac { m ^ { 2} } { m - 2} \div \frac { m ^ { 2} - 3m } { m ^ { 2} - 5m + 6}$ ?

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Answer 1 · 2018-03-10T13:47:50

$m$

We have the problem:

$m^2/(m-2)-:(m^2-3m)/(m^2-5m+6)$

1) Reciprocate the second term, and change the sign:

$=>m^2/(m-2) * (m^2-5m+6)/(m^2-3m)$

2) Factorize the terms:

$((m)(m))/((m-2)) * ((m-3)(m-2))/((m)(m-3))$

Cancelling out:

$(cancel((m))(m))/(cancel((m-2))) * (cancel((m-3))cancel((m-2)))/(cancel((m))cancel((m-3)))$

$=m/1 * 1/1$

$=1m$

$=m$

Thus, solved.

How do you divide and simplify \frac { m ^ { 2} } { m - 2} \div \frac { m ^ { 2} - 3m } { m ^ { 2} - 5m + 6}\frac { m ^ { 2} } { m - 2} \div \frac { m ^ { 2} - 3m } { m ^ { 2} - 5m + 6}?