How do you factor 4t^2+4t+14t2+4t+1?

1 Answer
Mar 9, 2018

(2t+1)(2t+1)(2t+1)(2t+1)

Explanation:

we are given:-

4t^2+4t+14t2+4t+1 resembles ax^2+bx+cax2+bx+c
here a=4,b=4 and c=1a=4,b=4andc=1
and since, sum=b=b,product=ac=ac

factors are the number which when you (multiply) and also when you (add) them give the same value for sum and product.

sum=4
product=4*1=4
factors=2 and 2

so
4t^2+2t+2t+14t2+2t+2t+1
2t(2t+1)+1(2t+1)2t(2t+1)+1(2t+1)

(2t+1)(2t+1)(2t+1)(2t+1)