How do you factor $4t^2+4t+1$ ?

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Answer 1 · 2018-03-09T10:18:52

$(2t+1)(2t+1)$

we are given:-

$4t^2+4t+1$ resembles $ax^2+bx+c$
here $a=4,b=4 and c=1$
and since, sum $=b$ ,product $=ac$

factors are the number which when you (multiply) and also when you (add) them give the same value for sum and product.

sum=4
product=4*1=4
factors=2 and 2

so
$4t^2+2t+2t+1$
$2t(2t+1)+1(2t+1)$

$(2t+1)(2t+1)$

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