How do you foil $(2x+4)(x+3)$ ?

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Answer 1 · 2018-03-05T07:03:17

$2x^2 + 10x + 12$

I use a method similar to multiplication; distribute first the $x$ and then the three.

$(2x + 4)$
$(x + 3)$

$2x^2 + 4x$

$" " " " +6x + 12$

Answer 2 · 2018-03-05T07:05:57

$(2x + 4)(x + 3) = 2x^2 + 10x + 12$

Expand the following binomial product:

$(2x + 4)(x + 3)$

First: $2x xx x$

Outside: $2x xx 3$

Inside: $4 xx x$

Last: $4 xx 3$

Now we can combine them by adding them together.

$2x xx x + 2x xx 3 + 4 xx x + 4 xx 3$

We can simplify from there.

$2x^2 + 6x + 4x + 12$

$2x^2 + 10x + 12$

Because there are no common factors here, we can not simplify it any further.

How do you foil (2x+4)(x+3)(2x+4)(x+3)?