How do you find all zeros of $h(t)=t^2-6t+9$ ?

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Answer 1 · 2018-03-05T06:09:48

3, that is the only root of $h(t)$ .

$h(t)$ is a quadratic in $t$ which is :
$h(t)=t^2-6t+9$
to find its zeros we equate the function with 0.
$h(t) = 0 => t^2-6t+9 = 0$

Now by splitting the middle term,
$=>t^2 -3t -3t +9= 0$
$=>t(t-3)-3(t-3) = 0$
$=>(t-3)(t-3) = 0$

Hence the root is 3.

How do you find all zeros of h(t)=t^2-6t+9h(t)=t^2-6t+9?