Calculate? the volume occupied by 8.8 gram of CO2 at 31.1 degree Celsius and 1 bar pressure R= 0.083 by LK inverse mole inverse( molecular mass of CO2=44 gram mole inverse)

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Calculate? the volume occupied by 8.8 gram of CO2 at 31.1 degree Celsius and 1 bar pressure R= 0.083 by LK inverse mole inverse( molecular mass of CO2=44 gram mole inverse)

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Answer 1 · 2018-03-05T02:46:08

$5.05 {L of CO}_{2}$ $5.05 "L of CO"_2$

Explanation:

Use givens with the gas law constant, here's the basic equation we used of the ideal gas law: $P V = n R T$ $PV= nRT$ , manipulated to $V = \frac{n R T}{P}$ $V=(nRT)/P$

$8.8 cancel("g CO"_2)* (1 cancel("mol CO"_2))/ (44.01 cancel("g CO"_2))* (0.083" L" cancel("bar"))/(cancel("mol")cancel( "K"))* (304.3 cancel("K"))/ (1 cancel("bar"))="5.05 L CO"_2"$

Stuff cancels out and you're left with $"L"$ of $"CO"_2"$

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Calculate? the volume occupied by 8.8 gram of CO2 at 31.1 degree Celsius and 1 bar pressure R= 0.083 by LK inverse mole inverse( molecular mass of CO2=44 gram mole inverse)

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