How do you simplify #(6i)(-8i)#?

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Answer 1 · 2018-03-04T11:28:17

48

Considering #i# as the imaginary number, defined as #i^2=-1#

#(6i)*(-8i)=(-8*6)i^2=-48i^2=48#

Answer 2 · 2018-03-04T11:28:56

It becomes 48.

If you multiply them together, you get #-48i^2#. Since #i# is #sqrt(-1) #, then #i^2= -1#. #-48*-1=48#. Hope this helped.