How do you find abs( 6-3i )?

2 Answers
Jim G.
Mar 3, 2018

3sqrt5

Explanation:

"given a complex number "z=x+yi" then"

•color(white)(x)|z|=|x+yi|=sqrt(x^2+y^2)

"here "x=6" and "y=-3

rArr|6-3i|=sqrt(36+9)=sqrt45=3sqrt5

Bhaskar B.
Mar 3, 2018

3sqrt 5

Explanation:

Any complex no. of the form z = x+iy has |z| =sqrt( x^2 + y^2)
So, here x = 6, y = -3.
So we get:
|z| = sqrt(6^2 + (-3)^2) = sqrt(36 + 9) = sqrt(45) = 3sqrt5

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