What is the perimeter of a triangle with corners at (6,5), (8,2), and (4,7)?

1 Answer

Perimeter = 62

Explanation:

Let (6,5) = A , (8,2) = B and (4,7) = C
Formula of distance between points is :
(x2x1)2+(y2y1)2
Find the distance between A and B:
Let (6,5) = (x1,y1) and (8,2) = (x2,y2)
(86)2+(25)2
(2)2+(3)2
(4+9)2
(13)2
13

Find the distance between B and C:
Let (8,2) = (x1,y1) and (4,7) = (x2,y2)
(48)2+(72)2
(4)2+(5)2
(16+25)2
(41)2
41

Find the distance between C and A:
Let (4,7) = (x1,y1) and (6,5) = (x2,y2)
(64)2+(57)2
(2)2+(2)2
(4+4)2
(8)2
8

Perimeter = AB+BC+CA
13+41+8
62