The equilibrium constant #K_c# for the reaction #N_2(g)# + #3H_2(g)# #rightleftharpoons# #2NH_3(g)# at #450^oC# is 0.159. What is the equilibrium composition when 1 mol #N_2# is mixed with 3 mol #H_2# in a 2.00-L vessel? Thank you so much!
1 Answer
Mar 2, 2018
2.07 mol of NH3
Explanation:
Kc =
[NH3] =
Plugging the value of N2 and H2 as 1 and 3 mol respectively, we get the equilibrium amount of NH3 as 2.07 mol.
