Please answer this question?

Question

Please answer this question?

1 Answer

Impact of this question

2633 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-02T16:28:43

See below.

Explanation:

For a biconvex lens we generally take $f = \frac{R}{2}$ $f=R/2$ (by generally i'm actually refering to a 10th gradier in India like me and ujjwal who has asked this question)

Now, using lens maker formula
meritnation

$\frac{1}{f} = (n - 1) (\frac{1}{R_{1}} - \frac{1}{R_{2}})$ $1/f = (n-1)(1/R_1 -1/R_2)$

In case $R_{1} = R_{2}$ $R_1 =R_2$
The formula becomes

$\frac{1}{f} = (n - 1) (\frac{2}{R})$ $1/f=(n-1)(2/R)$

Generally, we are too ignorant about n (refractive index) and we eliminate $(n - 1)$ $(n-1)$ as 1, this is what we have to do here.

Here $n - 1 = 1$ $n-1=1$ , you have to accept it for time being because of absence of proper details.

$\frac{1}{f} = (\frac{1}{R_{1}} - \frac{1}{R_{2}})$ $1/f=(1/R_1 -1/R_2)$ $" "$ ( $R_{2} = - \infty$ $R_2 =-oo$ )

$\frac{1}{f} = \frac{1}{R}$ $1/f=1/R$

mini physics
Now recall the ray diagrams , if object is at C the image will also be at C.

Now, since there is a mirror so to form image of object on object itself the object distance should be $10 c m$ $10cm$ .
Answer $= 10 c m$ $=10cm$

Science

Math

Humanities

... and beyond

Please answer this question?

1 Answer

Explanation:

Related questions

Impact of this question