How do you solve $4 (2 x + 4) + 4 (4 x + 5) + 5 = 24 x + 42$ $4( 2x + 4) + 4( 4x + 5) + 5= 24x + 42$ ?

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Answer 1 · 2018-03-02T15:14:23

No Solution

Breaking it down...

$4 (2 x + 4) = 4 \cdot 2 x + 4 \cdot 4 = 8 x + 16$ $4(2x+4) = 4*2x+4*4 = 8x+16$ .

$4 (4 x + 5) = 4 \cdot 4 x + 4 \cdot 5 = 16 x + 20$ $4(4x+5) = 4*4x+4*5 = 16x+20$

$8 x + 16 + 16 x + 20 + 5 = 24 x + 42$ $8x+16+16x+20+5=24x+42$

Combining Like Terms, $24 x + 41 = 24 x + 42$ $24x+41=24x+42$

Subtracting $41$ $41$ from both sides,

$24 x = 24 x + 1$ $24x=24x+1$

Subtracting $24 x$ $24x$ from Both Sides,

$0 = 0 + 1$ $0=0+1$ , or $0 = 1$ $0=1$ .

This is NOT Valid, so there is no Solution.

Awesome!

How do you solve 4( 2x + 4) + 4( 4x + 5) + 5= 24x + 424(2x+4)+4(4x+5)+5=24x+424( 2x + 4) + 4( 4x + 5) + 5= 24x + 42?