What is the product of #(14m^2n^5)(2m^5)?#

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Answer 1 · 2018-03-01T16:10:06

#28m^7n^5#

This is just a simple multiplication problem, dressed up with high power exponents and multiple variables.

To solve it, we use the same properties as solving something like

#2(2xy)#

However, we must pay attention to exponents.

When multiplying with the same base (m in this case) we add the powers.

Start by multiplying #14*2 = 28#

Next, multiply by #m^5#

We have #m^2# already, so we add the powers to get #m^7#.

And since we aren't multiplying by anything that contains n, we just leave it as is in our final answer.