What is the mass of 3 moles of $"C"_2"H"_2$ ?

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Answer 1 · 2018-02-26T17:46:29

$"78 g"$

Every mole of $"C"_2"H"_2$ (acetylene) has a mass of $"26.04 g"$ , i.e. acetylene has a molar mass of $"26.04 g/mol"$ .

Thus,

$"26.04 g/mol " * " 3 mol"$

gives you the mass of $3$ moles, $"78 g"$

Answer 2 · 2018-02-26T17:50:17

Molar mass of $C_2H_2 => 26g$ , that's the mass of 1 mole.

Therefore, mass of 3 moles of $C_2H_2$ would be $26 xx 3 = color(red)(78g$

Answer 3 · 2018-02-27T00:25:53

$78 \ "g"$

Acetylene $(C_2H_2)$ has a molar mass of $26.04 \ "g/mol"$ .

To find out the mass of moles, we have to multiply the number of moles by the molar mass of the substance, i.e. we can form an equation like this:

$"mass"="moles"*"molar mass"$

So, the mass of three moles of acetylene is

$"mass"_(C_2H_2)=3color(red)cancelcolor(black)"mol"*(26.04 \ "g")/(color(red)cancelcolor(black)"mol")=78.12 \ "g"$

Now, we can round off to the nearest whole number to make the answer more reasonable, so it'll be

$78.12 \ "g"~~78 \ "g"$

What is the mass of 3 moles of "C"_2"H"_2"C"_2"H"_2 ?